Suppose the following code is embedded in an otherwise correct and complete program. Answer below the question about what version of f() is called in g().

Question

```
void f(); //global
namespace A
{
void g()
{
f(); //Does this call A::f()? Or the global f()?
}
void f();

```
a) The call is to the global f();
b) The call is to the namespace A version of f(), i.e., A::f();
c) There is an error. There is a conflict between the namespace f() and the global
f(), so there is no call made at all
d) There are other errors that prevent the code from running.

Answer 1

a) The scope of an identifier starts at its declaration and runs until shadowed. In g(),
the global f() is in scope. A::f()is not available.
b) A use of a name refers to a global namespace version if not masked by a name
defined in the name space prior to the use. The definition of A::f() has not been
seen at the point that A::g() is invoked.
c) There is no conflict between global