Solve the equation for solutions in the interval [0°, 360°). Round to the nearest degree.sin 2? = cos ?
A. {105°, 165°, 285°, 345°}
B. {0°, 120°, 180°, 240°}
C. {30°, 90°, 150°, 270°}
D. {15°, 165°, 195°, 345°}
Answer: C
Mathematics
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Solve the initial value problem.Differential Equation: 
= (2 sec 2t tan 2t) i + 
j + t2kInitial Condition: r(0) = 7i + 
j - 5k
A. r(t) = (csc 2t + 6)i + 
j + 
k
B. r(t) = (sec 2t + 6)i - 
j + 
k
C. r(t) = (csc 2t + 6)i + 
j + (t3 - 5)k
D. r(t) = (sec 2t + 6)i + 
j + 
k
Mathematics
Evaluate the expression.3-2
A. -9
B. 9
C. 
D. 
Mathematics
Express the expanded form as a Hindu-Arabic numeral.(7 × 104) + (0 × 103) + (0 × 102) + (2 × 101) + (7 × 1)
A. 727 B. 70,027 C. 98 D. 7027
Mathematics
Insert <, >, or = to make the statement true.5 _____ -5
A. < B. > C. =
Mathematics