Solve using elimination.
A. x= 1, y = 3; x = 1, y = -3; x = -1, y = 3; x = -1, y = -3
or (1, 3), (1, -3), (-2, 3), (-2, -3)
B. x = 2, y = 3; x = 2, y = -3; x = -2, y = 3; x = -2, y = -3
or (2, 3), (2, -3), (-2, 3), (-2, -3)
C. x = 2, y = -3; x = -2, y = 3 or (2, -3), (-2, 3)
D. x = 1, y = 3; x = -1, y= -3 or (1, 3), (-1, -3)
Answer: B
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A. 2
B. 128
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Find the standard form of the equation of the hyperbola satisfying the given conditions.Foci: (-5, 0), (5, 0); vertices: (-2, 0), (2, 0)
A. -
= 1
B. -
= 1
C. -
= 1
D. -
= 1
Find the value of the exponential expression.33
A. 27 B. 33 C. 9 D. 2
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A. aa, ab, ac, ad, ae, af, ba, bb, bc, bd, be, bf, ca, cb, cc, cd, ce, cf, da, db, dc, dd, de, df, ea, eb, ec, ed, ee, ef, fa, fb, fc, fd, fe, ff P(6, 2) = 36 B. ab, ac, ad, ae, af, ba, bc, bd, be, bf, ca, cb, cd, ce, cf, da, db, dc, de, df, ea, eb, ec, ed, ef P(6, 2) = 25 C. ab, ac, ad, ae, af, ba, bc, bd, be, bf, ca, cb, cd, ce, cf, da, db, dc, de, df, ea, eb, ec, ed, ef, fa, fb, fc, fd, fe P(6, 2) = 30 D. ab, ac, ad, ae, af, bc, bd, be, bf, cd, ce, cf, de, df, ef P(6, 2) = 15