Use mathematical induction to prove the statement is true for all positive integers n. = (n + 2)(n + 1)

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First we show that the statement is true when n = 1.
 For n = 1, we get   = (1 + 2)(1 + 1)
 Since  =  = 6 = 3 ? 2 = (1 + 2)(1 + 1), P1 is true and the first condition for the principle of induction is satisfied.
Next, we assume the statement holds for some unspecified natural number k. That is,
Pk = (k + 2)(k + 1) is assumed true.
On the basis of the assumption that Pk is true, we need to show that Pk+1 is true. 
Pk+1 = ((k + 1) + 2)((k + 1) + 1)
So we assume that  is true and multiply both sides of the equation by  
 ?  = (k + 2)(k + 1) ? 
 = (k + 2)(k + 3) 
 = (k + 2)(k + 3)
 = ((k + 1) + 2)((k + 1) + 1)

 The last equation says that Pk+1 is true if Pk is assumed to be true. Therefore, by the principle of mathematical induction, the statement   = (n + 2)(n + 1) is true for all natural numbers n.

Mathematics

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