A wildlife biologist has spent the past 5 years studying the relationship between the length (inches) and the average weight (lb) of the striped bass. His results are summarized in the table below.
Length(inches)
Weight(lb)
14
3
18
6
22
11
26
14
Find the least squares regression line y = ax + b for the data in the table, where x represents the length of the fish in inches and y represents the weight in pounds. Use this regression line to estimate the average weight of a striped bass that is 21 inches in length.
A. y = 0.85(21) - 12.5 = 5.35 lb
B. y = 0.95(21) - 10.5 = 9.45 lb
C. y = 0.95(21) - 8.5 = 11.45 lb
D. y = 0.75(21) - 9.5 = 6.25 lb
E. y = 0.65(21) - 10.5 = 3.15 lb
Answer: B
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Provide an appropriate response.Suppose X is normally distributed with mean 80 and standard deviation 15. Without using tables, determine the approximate value of P(65 < X < 95).
A. 0.997
B. 0.33
C.
0.68 |
D. 0.95
E. 0.50
Find the expected value.Mr. Cameron is sponsoring an summer concert. He estimates that he will make $300,000 if it does not rain and make $60,000 if it does rain. The weather bureau predicts the chance of rain is 0.34 for the day of the concert. What are Mr. Cameron's expected concert earning?
A. $300,000 B. $360,000 C. $60,000 D. $218,400
Find the quotient.
A. 23
B. -33
C. -
D. -23