Find the vertex form for the quadratic function. Then find each of the following:(A) Intercepts(B) Vertex(C) Maximum or minimum(D) Rangef(x) = x2 + 4x + 3
A. Standard form: f(x) = (x + 2)2 - 1
(A) x-intercepts: - 3, -1; y-intercept: 3
(B) Vertex (2, -1)
(C) Minimum: -1
(D) y ? -1
B. Standard form: f(x) = (x - 2)2 - 1
(A) x-intercepts: - 3, -1; y-intercept: 3
(B) Vertex (-2, -1)
(C) Maximum: -1
(D) y ? -1
C. Standard form: f(x) = (x + 2)2 - 1
(A) x-intercepts: - 3, -1; y-intercept: 3
(B) Vertex (-2, -1)
(C) Minimum: -1
(D) y ? -1
D. Standard form: f(x) = (x - 2)2 - 1
(A) x-intercepts: 1, 3; y-intercept: 3
(B) Vertex (-2, -1)
(C) Minimum: -1
(D) y ? -1
Answer: C
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