Use the given table for y = ax2 + bx + c to solve ax2 + bx + c < 0 or ax2 + bx + c > 0, as indicated.y = x2 - 64; ax2 + bx + c < 0
A. x < -8 or x > 8
B. -9 < x < 9
C. x < -9 or x > 9
D. -8 < x < 8
Answer: D
Mathematics
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Factor the special products, which are the sum or difference of two perfect cubes.125x6 + 64y12
A. (5x2 - 4y4)( 5x2 + 4y4) B. (5x2 - 4y4)(25x2 + 20x2y4 + 16y8b2) C. (5x2 + 4y4)(25x4 - 20x2y4 + 16y8) D. (5x2 + 4y4)(25x4 + 20x2y4 + 16y8)
Mathematics
Solve by factoring and using the principle of zero products.20y2 + 37y + 15 = 0
A. - 
, - 
B. - 
, - 
C. 
, 
D. 
, - 
Mathematics
For each set described, write the set in roster form.{x|x is a negative number between 2 and 6}
A. {3, 4, 5} B. {2, 3, 4, 5} C. {3, 4, 5, 6} D. { } or ?
Mathematics
A. 
B. 
C. 
D. 
E. None of these
Mathematics