Among the cast aluminum parts manufactured on a certain day, 80% were flawless, 15% had only minor flaws, and 5% had major flaws. Find the probability that a randomly chosen part
a. has a flaw (major or minor).
b. has no major flaw.
(a) The events of having a major flaw and of having only minor flaws are mutually exclusive. Therefore
P(major flaw or minor flaw) = P(major flaw) + P(only minor flaws) = 0.15 + 0.05 = 0.20.
(b) P(no major flaw) = 1?P(major flaw) = 1?0.05 = 0.95.
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