A uniform rod of mass M = 1.2 kg and length L = 0.80 m, lying on a frictionless horizontal plane, is free to pivot about a vertical axis through one end, as shown. The rotational inertia of the rod about this axis is given by (1/3)ML2. If a force (F = 5.0 N, ? = 40°) acts as shown, what is the resulting angular acceleration about the pivot point?
?
?
A. 16 rad/s2
B. 12 rad/s2
C. 14 rad/s2
D. 10 rad/s2
E. 33 rad/s2
Answer: D
Physics & Space Science
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