A half-wave, single-phase ac-to-dc converter is loaded by an impedance of l0 mH inductance in series with l0 ? resistance. The ac voltage is 110 v (rms). For ? equal to 30o and 90o , calculate the following:
? = ° 10 , assuming that a freewheeling diode is used.
a. Conduction period
b. Average current of the load
c. Average voltage of the load
d. Power
? = 10
a. With a freewheeling diode, conduction angle of the
SCR = ) ? = ? ??(? = ? = 170o
b. Average Voltage = 49.1412 V (Eq. 3.38)
c. Average Current = 49.1412 V/R = 4.91412 A
d. Power = Power delivered by the source
Here, we use the power delivered by the source, because the power delivered to
the load (dissipated in R) during freewheeling actually comes from the energy
stored in the inductor when the SCR is conducting. We can also use the square of
the current as we did in Problem 3.1, but the power calculated in that manner will
always be an approximation since the angle ? when i(wt) dies down to zero will
have to be approximated by the angle at which i(wt) is very small.
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