Using the ideal gas law and the compressibility factor, determine the pressure of methane gas at a temperature of 300 K and specific volumes of (a) 0.005 m3/kg, (b) 0.05 m3/kg, (c) 0.5 m3/kg, and (d) 5.0 m3/kg
Given: CH4, T = 300 K
What will be an ideal response?
For CH4, R = 0.5182 kJ/kg-K
The pressure will be found by the following means:
Ideal Gas Law: P = RT/v
Compressibility factor: P = ZRT/v, where Z is found from the compressibility charts,
using the critical properties of methane: Tc = 191.1 K, Pc = 4640 kPa .
The reduced temperature is TR = T/Tc = 1.57
The pseudo-reduced specific volume is
The results for the pressure are as follows:
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