Find the expected value.Mr. Cameron is sponsoring an summer concert. He estimates that he will make $300,000 if it does not rain and make $60,000 if it does rain. The weather bureau predicts the chance of rain is 0.34 for the day of the concert. An insurance company is willing to insure the concert for $150,000 against rain for a premium of $30,000. If he buys this policy, what are his expected earnings from the concert?
A. $180,000
B. $300,000
C. $270,000
D. $239,400
Answer: D
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Solve the problem.A company estimates that the revenue (in dollars) from the sale of x units of doghouses is given by 
Use the differential to approximate the change in revenue from the sale of one more doghouse when 850 doghouses are sold.
A. $70.00 B. $0.87 C. $0.70 D. $87.00
Solve the equation.
+ 
= -23
A. 
B. 
C. 
D. 
Solve the problem.Find the values of a, b, and c such that the graph of the quadratic equation 
passes through the points 
and 
A. a = 1; b = 5; c = -1 B. a = -1; b = -1; c = 5 C. a = -1; b = 5; c = -1 D. a = 1; b = -1; c = 5
Solve the problem.In one study, a type of fish was exposed to a toxin. The table lists toxin concentrations in the fish after a certain number of hours. The concentration C of the toxin in the fishes' bloodstream was measured in micrograms of toxin per gram of fish after x hours of exposure. 
(i) Describe the relationship between x and C; (ii) Use regression to find a cubic polynomial function f(x) that models the data; (iii) graph C and the data; (iv) Concentrations above 30 are lethal to the fish. Determine how many hours of exposure it takes for this to occur.
A. (i) As x increases, C increases;
(ii) f(x) ? 0.38x3 - 4.35x2 + 22.97x - 33.40
(iii)
(iv) x ? 6.0 (approximately)
B. (i) As x increases, C increases;
(ii) f(x) ? 0.28x3 - 4.35x2 + 24.97x - 33.40
(iii)
(iv) x ? 7.9 (approximately)
C. (i) As x increases, C increases;
(ii) f(x) ? 0.28x3 - 5.35x2 + 22.97x - 33.40
(iii)
(iv) x ? 6.2 (approximately)
D. (i) As x increases, C increases;
(ii) f(x) ? 0.38x3 - 5.35x2 + 24.97x - 33.40
(iii)
(iv) x ? 9.1 (approximately)