Calculate the flux of the field F across the closed plane curve C.F = e4xi + e2yj; the curve C is the closed counterclockwise path around the triangle with vertices at  (4, 0), and (0, 2)

A. 0
B. e16(1 - e-16) + 1(e4 - 1) - 6
C. e16(1 - e-4) + 1(e4 - 1) + 6
D. e16( e-4 - 1) + 1(1 - e4) - 6


Answer: B

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