Use the principle of mathematical induction to show that the mathematical statement is true for all natural numbers n.Sn: 1 ? 6 + 2 ? 6 + 3 ? 6 + . . . + 6n = 

What will be an ideal response?


S1:1 ? 6 
 
 6 = 6 ?
Sk: 1 ? 6 + 2 ? 6 + 3 ? 6 + . . . + 6k = 
Sk+1: 1 ? 6 + 2 ? 6 + 3 ? 6 + . . . + 6(k + 1) = 
We work with Sk. Because we assume that Sk is true, we add the next consecutive term, namely
6(k+1), to both sides."

1 ? 6 + 2 ? 6 + 3 ? 6 + . . . + 6k + 6(k + 1) =  + 6(k + 1)
1 ? 6 + 2 ? 6 + 3 ? 6 + . . . + 6(k + 1) =  + 
1 ? 6 + 2 ? 6 + 3 ? 6 + . . . + 6(k + 1) = 
1 ? 6 + 2 ? 6 + 3 ? 6 + . . . + 6(k + 1) = 
We have shown that if we assume that Sk is true, and we add (6(k+1) to both sides of Sk , then Sk+1 is also true. By the principle of mathematical induction, the statement Sn is true for every positive integer n.

Mathematics

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Construct a truth table for the statement.~q ? (~p ? q)

A.

TTFFFF
T F F T T T
F T T F F T
F F T T T T
B.
TTFFTT
T F F T F T
F T T F F F
F F T T T T
C.
TTFFFF
T F F T F F
F T T F F T
F F T T T T
D.
TTFFTT
T F F T F T
F T T F T T
F F T T T T

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A. (2, 2)
B. (-2, -2)
C. (2, 2)
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Translate the phrase into a mathematical expression. Use x to represent "a number". The quotient of a number and 4

A. x - 4
B.  
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D.

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