Use the principle of mathematical induction to show that the mathematical statement is true for all natural numbers n.Sn: 1 ? 6 + 2 ? 6 + 3 ? 6 + . . . + 6n = 
What will be an ideal response?
S1: | 1 ? 6 ![]() ![]() |


6 = 6 ?
Sk: 1 ? 6 + 2 ? 6 + 3 ? 6 + . . . + 6k =

Sk+1: 1 ? 6 + 2 ? 6 + 3 ? 6 + . . . + 6(k + 1) =

We work with Sk. Because we assume that Sk is true, we add the next consecutive term, namely
6(k+1), to both sides."
1 ? 6 + 2 ? 6 + 3 ? 6 + . . . + 6k + 6(k + 1) =

1 ? 6 + 2 ? 6 + 3 ? 6 + . . . + 6(k + 1) =


1 ? 6 + 2 ? 6 + 3 ? 6 + . . . + 6(k + 1) =

1 ? 6 + 2 ? 6 + 3 ? 6 + . . . + 6(k + 1) =

We have shown that if we assume that Sk is true, and we add (6(k+1) to both sides of Sk , then Sk+1 is also true. By the principle of mathematical induction, the statement Sn is true for every positive integer n.
Mathematics
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