The optimal solution:
Consider the following maximization problem.
MAX z = x + 2y
s.t.
2x + 3y ? 6
5x + 6y ? 30
y ? 1
A) occurs where x = 4.67 and y = 1.11.
B) occurs where x = 0 and y = 2.
C) occurs where x = 6 and y = 0.
D) results in an objective function value of 12.
Answer: B
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