A 72.0-kg person pushes on a small doorknob with a force of 5.00 N perpendicular to the surface of the door. The doorknob is located 0.800 m from axis of the frictionless hinges of the door

The door begins to rotate with an angular acceleration of 2.00 rad/s2. What is the moment of inertia of the door about the hinges?
A) 4.28 kg ? m2
B) 7.52 kg ? m2
C) 1.88 kg ? m2
D) 0.684 kg ? m2
E) 2.74 kg ? m2


Answer: C

Physics & Space Science

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