Solve the initial value problem.Differential Equation: 
= (3 sec 3t tan 3t) i + 
j + t2kInitial Condition: r(0) = 9i + 
j - 5k
A. r(t) = (sec 3t + 8)i - 
j + 
k
B. r(t) = (csc 3t + 8)i + 
j + (t3 - 5)k
C. r(t) = (csc 3t + 8)i + 
j + 
k
D. r(t) = (sec 3t + 8)i + 
j + 
k
Answer: D
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C. 
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