Solve the problem.A simple electrical circuit consists of a resistor connected between the terminals of a battery. The voltage V (in volts) is dropping as the battery wears out. At the same time, the resistance R (in ohms) is increasing as the resistor heats up. The power P (in watts) dissipated by the circuit is given by P = 
. Use the equation
= 
+
src="https://sciemce.com/media/4/ppg__wra0609191916__f1q193g5.jpg" style="vertical-align: -17.0px;" /> 
to find how much the power is changing at the instant when R = 4 ohms, V = 2 volts, 
and dV/dt = -0.08 volts/sec.
A. -0.92 watts
B. -1.08 watts
C. 0.92 watts
D. 1.08 watts
Answer: B
Mathematics
src="https://sciemce.com/media/4/ppg__wra0609191916__f1q193g5.jpg" style="vertical-align: -17.0px;" /> to find how much the power is changing at the instant when R = 4 ohms, V = 2 volts, and dV/dt = -0.08 volts/sec.
A. -0.92 watts
B. -1.08 watts
C. 0.92 watts
D. 1.08 watts
Answer: B
Mathematics
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