The circuit below contains 5 identical light bulbs. The emf is 110 V. Which light bulb(s) is(are) brightest?
A. A: The one closest to the positive terminal of the battery.
B. A and C: The bulbs closest to the positive terminal of the battery.
C. A and B: Because they are closest to the terminals of the battery.
D. C and D: Because they receive current from A and B and from E.
E. E: Because the potential difference across E is that of the battery.
Answer: E
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