The temperature increases from 20ºC to 99ºC in 2 kg of both water and lead. The percent difference between the internal energy change of the lead compared to that of the water is nearest:”
A) 62%
B) 85%
C) 92%
D) 97%
D) 97%
U water = mC p T = 2× 4. 18× ( 99 ? 20) = 660 kJ
U lead = mC p T = 2 × 0. 13× ( 99 ? 20) = 20.5 kJ
660 ? 20.5
? % difference =_____________ × 100 = 0.969 or 97%
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