A motorcycle engine produces 25 hp of power at a thermal efficiency of 0.25. Determine the heat input rate from the combustion process (in Btu/h) as well as the rate of heat lost to the environment.

Given: W?=25 hp=17.67 Btu/s; n = 0.25
Assume: The engine is a cyclic heat engine.

What will be an ideal response?


Solution: Q?H=W?/n = 70.7 Btu/s
For a cycle: Wcycle = Qcycle
There are two heat transfers and one power, so Q?cycle=Q?H+Q?C=W?
So, ????? ????= --53.0 Btu/s

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