Use mathematical induction to prove that the statement is true for every positive integer n.2n > n
What will be an ideal response?
Answers will vary. One possible proof follows.
a). Let n = 1. Then, 31 = 3 > 1, so the statement is true for n = 1.
b). Assume that the statement is true for n = k:
3k > k
Multiply both sides by 3:
3?3k = 3k+1 > 3k
Also, since k ? 1, then 2k > 1, which can be re-written as 3k > k + 1. Thus,
3k+1 > k + 1
Since the statement is true for n = k + 1 as long as it is true for n = k, and since the statement is true for n = 1, then it is true for all natural numbers n.
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What will be an ideal response?
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Write each fraction as an equivalent fraction with the LCD of the two fractions as the denominator.,
and
A. ;
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B. ;
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C. ;
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D. ;
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