The transfer function of the second-order bandpass filter is given by
a1 = 11090.1553, a0 = 3.153141×108
0 ? = a 0= 17757.0859 rad/s
The Q value is given by
Q = ? a1
0= 1.60116
The normalized component values are given by
C1 = 2 = 1.4142 F, C2 = 2 = 1.4142 F, R2 = 1 ?, R3 = 1 ?, RB = 1 ? , RA = 3 – 2 /Q = 2.1168 ?, K = 4 - 2 /Q = 3.1168, Ra = K/(4 - K) = 3.5288 ?, Rb = K/(2K-4) = 1.3955 ?
Application of the magnitude scaling (km = 1000) and frequency scaling (kf = ?0 = 17757.0859) yields
C1 = 1.4142
F k m k× f= 79.6422 nF
C2 = 1.4142
F k m k× f= 79.6422 nF
R2 = 1×1000 ? = 1 k?
R3 = 1×1000 ? = 1 k?
RB = 1×1000 ? = 1 k?
RA = 2.1168 ×1000 ? = 2.1168 k?
Ra = 3.5288 ×1000 ? = 3.5288 k?
Rb = 1.3955 ×1000 ? = 1.3955 k?
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