Solve the initial value problem.Differential Equation:   =  (t + 5)3/2i + etjInitial Condition:  r(0) = 0

A. r(t) = [(t + 5)7/2 - 57/2]i + (et - 1)j
B. r(t) = (t + 5)5/2i + etj
C. r(t) = [(t + 5)5/2 + 55/2]i + (et + 1)j
D. r(t) = [(t + 5)5/2 - 55/2]i + (et - 1)j


Answer: D

Mathematics

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