In the circuit shown below, let
Use nodal analysis to find V1, V2, and V3.
Vs1=6;Vs2=1;R1=1000;R2=1500;R3=2500;R4=1200;R5=800;
syms V1 V2 V3
[V1,V2,V3]=solve((V1-Vs1)/R1+(V1-V2)/R2+(V1-V3)/R3,...
(V2-V1)/R2+V2/R4+(V3-V1)/R3+V3/R5,...
V3==V2+Vs2,V1,V2,V3)
V1=vpa(V1,7)
V2=vpa(V2,7)
V3=vpa(V3,7)
I1=(Vs1-V1)/R1
I2=(V1-V2)/R2
I3=(V1-V3)/R3
I4=V2/R4
I5=V3/R5
7
IVs2=I2-I4
I5a=I3+IVs2
Answers:
V1 =
3.425026
V2 =
0.6359876
V3 =
1.635988
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