If a projectile is launched straight upward from the ground with an initial velocity of v0 (in feet/second), then the height (in feet) of the projectile after t seconds is given by the expression -16t2 + v0t. Find the height of the projectile (in feet) that was launched with the given initial velocity after t seconds.150 feet/second, 7 seconds

A. 266 feet
B. 38 feet
C. 938 feet
D. 1834 feet


Answer: A

Mathematics

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