Answer the question or provide the appropriate response.Which of the following methods may be used to show that there cannot be two real numbers that have a difference of 6 and a product of -24? (More than one method may be correct.)(i) Graph the function y = x2 - 6x + 24 and observe that the graph has no x-intercepts.(ii) Determine that the discriminant of the equation x2 - 6x + 24 = 0 is negative.(iii) Graph the function y = x2 - 6x + 24 and observe that the vertex lies above the x-axis.(iv) Graph the functions y1 = x2 - 6x and y2 = 24 and observe that these graphshave no points of intersection.
A. (i), (ii), (iii), (iv)
B. (i), (iv)
C. (i) only
D. (i), (ii), (iv)
Answer: A
Mathematics
You might also like to view...
Use the graph to find a ? > 0 such that for all x, 0 < 
< ? ? 
< ?.
A. 0.24 B. 2 C. 0.27 D. 0.51
Mathematics
Provide an appropriate response.Define f(0, 0) in a way that extends f(x, y) = 
to be continuous at the origin.
A. f(0, 0) = 0 B. f(0, 0) = 2 C. f(0, 0) = 8 D. f(0, 0) = 16
Mathematics
Use the equation and the corresponding graph for the quadratic function to find what is requested.f(x) = (x - 1)2 - 2
Find the equation of the axis.
A. x = 1 B. y = 2 C. x = -1 D. y = -2
Mathematics
Divide.0.074 ÷ 10
A. 0.74 B. 0.0074 C. 0.00074 D. 7.4
Mathematics