Answer the question by finding the linearization P1(x) of f at the given value of x.f(x) = e6x, at x = 0. Evaluate P1(0.06) and compare this value to f(0.06).
A. P1(0.06) = 1.11
f(0.06) = 1.433
B. P1(0.06) = 1.36
f(0.06) = 36.598
C. P1(0.06) = 1.36
f(0.06) = 1.433
D. P1(0.06) = 4.60
f(0.06) = 36.598
Answer: C
Mathematics
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