Solve the initial value problem.Differential Equation: 
= -6ti + 7tj + 10tkInitial Condition: r(0) = -4i + 5k
A. r(t) = (-6t2 - 8)i + 7t2j + (10t2 + 10)k
B. r(t) = 
i + 
t2j + 
k
C. r(t) = 
i + 
t2j - 
k
D. r(t) = 
i + 
t2j + 
k
Answer: D
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