This problem is based on the following cash flows for alternatives X and Y at an interest rate of 10% per year.
 FIGURE 1.png)
In comparing the alternatives on a future worth basis, the FW of machine X is closest to:
(a) $23,160
(b) $40,560
(c) $58,950
(d) $71,860
FWX = -146,000(F/P,10%,6) + (80,000-15,000)(F/A,10%,6) - 136,000(F/P,10%,3) + 10,000
= -146,000(1.7716) + (65,000)(7.7156) - 136,000(1.3310) + 10,000
= $71,861
Answer is (d) $71,860
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