Solve the initial value problem.Differential Equation: 
= (-cos t)i + (4t3- 2)jInitial Condition: r(0) = 9j
A. r(t) = (sin t)i + (12t2 + 9)j
B. r(t) = (-sin t)i + (t4)j
C. r(t) = (-sin t)i + (t4 + 9)j
D. r(t) = (-sin t)i + (t4- 2t + 9)j
Answer: D
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