The following problem is based on the these cash flows and an interest rate of 10% per year.
 FIGURE 1.png)
The annual worth of perpetual service for alternative X is represented by the following equation:
(a) ?200,000(0.10) ? 60,000 + 20,000(0.10)
(b) ?200,000(A?P,10%,5) ? 60,000 + 20,000(A?F,10%,5)
(c) ?200,000(A?P,10%,5) ? 60,000 ? 20,000(A?F,10%,5)
(d) ?200,000(0.10) ? 60,000 + 20,000(A?F,10%,5)
(b) ?200,000(A?P,10%,5) ? 60,000 + 20,000(A?F,10%,5)
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