Provide an appropriate response.If a body of mass m falling from rest under the action of gravity encounters an air resistance proportional to two times the square root of velocity, then the body's velocity t seconds into the fall satisfies the equation: m
= mg - 2kv2where k is a constant that depends on the body's aerodynamic properties and the density of the air.Determine the equilibrium, velocity curve, and the terminal velocity for a 140 lb skydiver (mg = 140) with k = 0.005.
A. Equilibrium: v = 
vterminal = 118.32 ft/sec
B. Equilibrium: v = 
vterminal = 118.32 ft/sec
C. Equilibrium: v = 
vterminal = 118.32 ft/sec
D. Equilibrium: v = 
vterminal = 118.32 ft/sec
Answer: D
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A. 
B. 
C. 
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