When the expression value % 2 evaluates to 0, the integer is even, so the first case executes. However, because there is no break statement in the first case, the statement at line 7 will also execute. So outputJTextField will always contain "Odd Integer" after the preceding switch statement executes.

Question

```
1 switch ( value % 2 )
2 {
3 case 0:
4 outputJTextField.setText( "Even Integer" );
5
6 case 1:
7 outputJTextField.setText( "Odd Integer" );
8 break;
9
10 } // end switch
```

Answer 1

When the expression value % 2 evaluates to 0, the integer is even, so the first case executes. However, because there is no break statement in the first case, the statement at line 7 will also execute. So outputJTextField will always contain "Odd Integer" after the preceding switch statement executes.

```
1 switch ( value % 2 )
2 {
3 case 0:
4 outputJTextField.setText( "Even Integer" );
5 break;
6
7 case 1:
8 outputJTextField.setText( "Odd Integer" );
9 break;
10
11 } // end switch
```