Solve the problem.One of the dimensions d (in) of the support columns of a building satisfies the equation 3d3 - 15d2 + 2700d - 13,500 = 0.What is d?
A. 2 in.
B. 5 in.
C. 3 in.
D. 1 in.
Answer: B
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Provide an appropriate response.Find a quadratic function f having x-intercepts -9 and -2 and y-intercept 6.
A. f(x) = 
x2 - 
x + 6
B. f(x) = x2 + 11x + 18
C. f(x) = 
x2 + 
x + 6
D. f(x) = x2 + 5x + 6
Use Descartes' Rule of Signs to determine the possible number of positive real zeros and the possible number of negative real zeros for the function.f(x) = 8x6 - 5x4 - 6x3 + 6x2 - 5x
A. 1 or 3 positive; 2 negative B. 0 or 2 positive; 1 or 3 negative C. 0 or 2 positive; 0 negative D. 1 or 3 positive; 0 or 2 negative
Set the viewing rectangle of your graphing calculator to 
by 
to solve the problem.Find a set of parametric equations evaluated over 0 ? t ? 2? that produces the graph shown.
A.
| x1 = 3 + 6cos(t), | y1 = -2 + 6sin(t) |
| x2 = 3 + 3cos(t), | y2 = 2.5 + 3sin(t) |
| x3 = 3 + 3cos(t), | y3 = -6.5 + 3sin(t) |
B.
| x1 = 3cos(t), | y1 = 3sin(t) |
| x2 = 1.5cos(t), | y2 = 4.5 + 1.5sin(t) |
| x3 = 1.5cos(t), | y3 = -4.5 + 1.5sin(t) |
C.
| x1 = 3 + 3cos(t), | y1 = -2 + 3sin(t) |
| x2 = 3 + 1.5cos(t), | y2 = 2.5 + 1.5sin(t) |
| x3 = 3 + 1.5cos(t), | y3 = -6.5 + 1.5sin(t) |
D.
| x1 = 3 + 3cos(t), | y1 = -2 + 3sin(t) |
| x2 = 3 + 1.5cos(t), | y2 = 2.5 + 1.5sin(t) |
| x3 = 3 + 1.5cos(t), | y3 = 5.5 + 1.5sin(t) |
Solve.
+ 
= 2
A. 2 B. 1 C. 0 D. 16