Charge in an Electric Field: A proton is placed in an electric field of intensity 800 N/C. What are the magnitude and direction of the acceleration of the proton due to this field? (e = 1.60 × 10-19 C, mproton = 1.67 × 10-27 kg)
A. 7.66 × 109 m/s2 opposite to the electric field
B. 7.66 × 1010 m/s2 opposite to the electric field
C. 7.66 × 1010 m/s2 in the direction of the electric field
D. 76.6 × 1010 m/s2 opposite to the electric field
E. 76.6 × 1010 m/s2 in the direction of the electric field
Answer: C
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