Solve the differential equation subject to the given condition. Note that y(a) denotes the value of y at t = a. 
= 0.18y, y(11) = 3550
A. y = 3550 e0.18(t- 11)
B. y = 0.18 e3550(t- 11)
C. y = 35500.18(t- 11)
D. y = 3550 e0.18(t+ 11)
Answer: A
Mathematics
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