Find a function P(x) of least possible degree, having real coefficients, with the given zeros.7 and 1 - 4i
A. P(x) = x3 - 5x2 + 3x + 119
B. P(x) = x3 - 5x2 + 3x - 119
C. P(x) = x3 - 9x2 + 31x - 119
D. P(x) = x3 + 9x2 + 31x - 119
Answer: C
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Solve the problem.The length of a rectangular box is more than its width, and its height is
more than its width. If the volume of the box is exactly 1000.00 inches3, what is the width of the box?
A. 9.3333 in. B. 9.0337 in. C. 9.0 in. D. 9.0333 in.
Find a polynomial of degree 3 with real coefficients that satisfies the given conditions.Zeros of -6, i, -i and P(-3) = 60
A. P(x) = -2x3 - 12x2 - 2x - 12 B. P(x) = -2x3 - 12x2 + 2x + 12 C. P(x) = 2x3 + 12x2 + 2x + 12 D. P(x) = 2x3 + 12x2 - 2x - 12
Determine whether or not the graph represents a function.
A. function B. not a function
Rotate the axes so that the new equation contains no xy-term. Discuss the new equation.x2 + 2xy + y2 - 8x + 8y = 0
A. ? = 36.9° +
= 1
ellipse
center (0, 0)
major axis is x'-axis
vertices at (±2, 0)
B. ? = 45°
y'2 = -4x'
parabola
vertex at (0, 0)
focus at (-, 0)
C. ? = 45°
x'2 = -4y'
parabola
vertex at (0, 0)
focus at (0, -)
D. ? = 36.9° +
= 1
ellipse
center (0, 0)
major axis is x'-axis
vertices at (±2, 0)