Solve the problem.The gravitational attraction A between two masses varies inversely as the square of the distance between them. If the force of attraction is 4 lb when the masses are 3 ft apart, what is the attraction when the masses are 6 ft apart?
A. 4 lb
B. 3 lb
C. 1 lb
D. 2 lb
Answer: C
Mathematics
You might also like to view...
Evaluate the line integral along the curve C.
ds , C is the path from (0, 0, 0) to (-4, 4, 1) given by:C1: r(t) = -4t2i + 4tj, 0 ? t ? 1C2: r(t) = -4i + 4j + (t-1)k, 1 ? t ? 2
A. 
B. 
- 
C. 
+ 
D. 
Mathematics
Use a product-to-sum identity to rewrite the expression.sin 35° cos 16°
A. 0.5(cos(19°) - cos(51°) ) B. 0.5(cos(51°) + cos(19°) ) C. 0.5(sin(51°) + sin(19°) ) D. 0.5(sin(19°) + sin(51°) )
Mathematics
Find the difference.33.54 - 26
A. 59.54 B. 7.54 C. 8.04 D. 7.64
Mathematics
Graph the ellipse and label the center.
+ 
= 1
A. C(2, 7)
B. C(2, -7)
C. C(-2, 7)
D. C(-2, -7)
Mathematics