Solve the problem.Find the point on the curve of intersection of the paraboloid 
and the plane 
that is closest to the origin.
A. (1, 1, -1)
B. (1, 1, 1)
C. (-1, 1, 1)
D. (1, -1, 1)
Answer: C
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372 ÷ 12.0
A. 32 B. 3.1 C. 310 D. 31
Multiply.
A. p4 - 8p2q2 B. p4 + 8p3q- 16p2q2 C. p4 - 8pq D. p4 - 16p2q2
Write the polynomial in standard form. Then find its degree and leading coefficient.6 + 2x4 - 6x5
A. 6 + 2x4 - 6x5 , degree: 5, leading coefficient: 6 B. -6x5 + 2x4 + 6, degree: 5, leading coefficient: -6 C. -6x5 + 2x4 + 6, degree: 9, leading coefficient: -6 D. 6 + 2x4 - 6x5 , degree: 10, leading coefficient: 6
Use the discriminant to find what type of solutions (two rational, two irrational, one rational, or two nonreal complex) each of the following equations has. Do not solve the equation.x2 - 4x + 7 = 0
A. one rational solution B. two irrational solutions C. two rational solutions D. two nonreal complex solutions