Solve.39% of what is 78?
A. 2000
B. 0.5
C. 200
D. 50
Answer: C
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Write in exponential form.log416 = 2
A. 162 = 4 B. 416 = 2 C. 42 = 16 D. 24 = 16
Factor the polynomial completely.120x9y9 - 84x2y6 - 48x4y4
A. 12(10x9y9 - 7x2y6 - 4x4y4) B. 12x2y4(10x7y5 - 7y2 - 4x2) C. 12x2(10x7y9 - 7y6 - 4x2y4) D. x2y4(120x7y5 - 84y2 - 48x2)
When a satellite is near Earth, its orbital trajectory may trace out a hyperbola, a parabola, or an ellipse. The type of trajectory depends on the satellite's velocity V in meters per second. It will be hyperbolic if 
, parabolic if 
, and elliptical if 
, where k = 2.82 × 107 is a constant and D is the distance in meters from the satellite to the center of Earth. Solve the problem.When a certain satellite was at a maximum distance of 57.6 × 106 m
from Earth's center, it had a velocity of 4873 m per sec. Determine the shape of its trajectory. A. parabolic B. elliptical C. hyperbolic
Evaluate.
