How many lineal feet of 4-inch-wide rubber base is needed for the office building in Figure 16.15? The doors are 3 feet wide and base is not needed on the outside of the exterior walls. Add 5 percent for waste. How many gallons of adhesive are needed using a coverage of one gallon per 150 square feet of base?
What will be an ideal response?
The amount of base is calculated as follows:
Gross length of base = 2 × (11?9? + 28?4?) + 2 × (11?9? + 11?6?) + 2 × (11?9? + 11?10?)
+ 2 × (11?9? + 11?10?) + 2 × (11?9? + 15?10?)
Gross length of base = 276?2?
Deduct for doors = 4.5 × 2 sides × 3? = 27?
Net length of base = 276?2? – 27? = 249?2?
Add waste.
Net length of base = 249?2? × 1.05 = 262 ft
Area of base = 249?2? × 4? / 12 in per ft = 83 sf
Gallon of adhesive = 83 sf / 150 sf per gallon = 0.55 gallons – Order 1 gallon
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