A reversible heat engine receives 500 kW of heat from a reservoir at 750 K and rejects 200 kW of heat to the low-temperature reservoir. What is the temperature of the low-temperature reservoir?

Given: TH = 750 K; Q?H=500 kW; QC?=?200 kW


For a heat engine, n = W?/Q?H
For a cycle, such as this heat engine, Wcycle = Qcycle
There are two heat transfers and one power, so Q?cycle=Q?H+Q?C=W?
So, W?= 300 kW
Then, ? = 300 kW/500 kW = 0.600
As this is a reversible heat engine, n = nmax = 1 – TC/TH = 0.600
Solving for TC = 300 K

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