Model the problem with a linear equation.An investment is worth $3104 in 2008. By 2011 it has grown to $3950. Let y be the value of the investment in the year x, where x = 0 represents 2008. Write a linear equation that models the value of the investment in the year x.
A. y = -282x + 4796
B. y = 282x + 3104
C. y = -282x + 3104
D. y = 
x + 3104
Answer: B
Mathematics
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A. 
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, find 
f(x).
A. 
; limit = -0.125
B. 
; limit = 0.225
C. 
; limit = 0.025
D. 
; limit = 0.125
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B. f-1(x) = 
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A. 
B. 
C. 
D. 
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