Factor completely.64a6 + b3a3
A. a3(4a - b)(16a2 + 4ab + b2)
B. a3(4a + b)(16a2 - 4ab + b2)
C. (4a2 + ba)(16a4 - 4ba3 + b2a2)
D. a3(4 + ab)(16 - 4ab + b2a2)
Answer: B
Mathematics
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and 
.
A. 
B. 
C. 
D. 
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A. 
= - 
B. 
= - 
C. 
= 
D. 
= - 
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A. -4
B. - 
C. 
D. 4
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Factor completely.x3 + 2x + x2 + 2
A. (x2 + 2)(x + 1) B. (x2 + 1)(2x + 1) C. (2x + 1)(x + 1) D. (x2 + 1)(x + 2)
Mathematics