A proposed highway has two tangents of bearings N 45º54’36” E and N 1º22’30” W. The highway design engineer, attempting to obtain the best fit for the simple circular curve to join these tangents, decides that the external ordinate is to be 43.00 ft. The PI is at station 65+43.21 Determine the following below:
(a) The central angle of the curve
(b) The radius of the curve
(c) The length of the tangent of the curve
(d) The station of the PC
(e) The length of the curve
(f) The station of the PT
(g) The deflection angle and chord from the PC to the first full station on the curve
What will be an ideal response?
(a) ? = 45.91° + 1.375° = 47.285°
(b) 
(c) T = 469.30 tan (47.285/2) = 205.44 ft
(d) Station of the PC = (65+43.21) – 205.44 ft = 63+37.76
(e) L = ?(469.30)(47.285)/180 = 387.31 ft
(f) Station of the PT = (63+37.76) + 387.31 ft = 67+25.07
(g) Deflection angle from the PC to the first full station:
DA1 = ?1?/2L = (100 – 37.76)(47.285)/(2)(387.31) = 3.7993°
Chord from the PC to the first full station:
C1 = 2(469.30) sin (3.7993) = 62.19 ft
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