Find the acceleration vector in terms of ur and u?.r = 2 cos 4t and ? = 3t
A. a = (-50 sin 4t)ur - 48 cos 4tu?
B. a = (-50 cos 3t)ur - 48 sin 3tu?
C. a = (-50 cos 4t)ur - 48 sin 4tu?
D. a = (-50 cos 4t)ur + 48 sin 4tu?
Answer: C
Mathematics
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Solve the problem.Find the tangent to y = cot x at x = 
.
A. y = 2x + 1
B. y = -2x + 
+ 1
C. y = -2x + 
D. y = 2x - 
+ 1
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Evaluate the expression.
A. 181,440 B. 504 C. 60,480 D. 84
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Rewrite the expression as a single logarithm.4 log5(5x + 6) + 3 log5(6x - 6)
A. log5((5x + 6)4(6x - 6)3)
B. log5 
C. log5((5x + 6)4 + (6x - 6)3)
D. 12 log5((5x + 6)(6x - 6))
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Write the number in scientific notation.0.00004822
A. 4.822 × 105 B. 4.822 × 10-4 C. 4.822 × 10-5 D. 4.822 × 104
Mathematics