Let C(t) be the number of leaves in a binary tree rooted at t. Assume
that isLeaf(t) returns 1 if t is a leaf and 0 otherwise. Which of the
following observations leads to a recursive implementation?
a. C(t)=C(t->left)+C(t->right)
b. C(t)=C(t->left)+C(t->right)+1
c. C(t)=C(t->left)+C(t->right)+isLeaf(t)
d. C(t)=C(t->left)+C(t->right)+isLeaf(t)+1
e. none of the above
C
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