Solve the problem.Meisha has $25,000 that she wants to invest. She invests it in accounts paying 12%, 7%, and 6% simple interest. The account paying 12% is a higher-risk account, so she wants the amount in that account to be half of the amount she has in the account paying 6% simple interest. If her annual interest is $1945, how much is invested at each rate?
What will be an ideal response?
$6500 at 12%, $5500 at 7%, $13,000 at 6%
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Which number is larger?
, 0.36
A. 
B. 0.36
Refer to a normal distribution described by the following figure. The mean is ? and the standard deviation is ?.
A data value of 40.5 corresponds to a standardized value of
A. -1.5. B. -1. C. 12. D. 0. E. none of these
Solve the problem.Find the amount in a savings account at the end of 10 years if the amount originally deposited is $7000 and the interest rate is 7% compounded semiannually.Use: A = P
ntwhere:A = final amountP = $7000 (the initial deposit)r = 7% = 0.07 (the annual rate of interest)n = 2 (the number of times interest is compounded each year)t = 10 (the duration of the deposit in years)
A. $9874.19 B. $13,928.52 C. $15,321.37 D. $144,900.00
Write interval notation for the following. Then graph the interval on a number line.{x? x ? -0.5}
A. (-?, -0.5)
B. [-0.5, ?)
C. (-?, -0.5]
D. (-0.5, ?)