Write a function that lists the number of ordinary files, directories, block special files, character special files, FIFOs, and symbolic links in the working directory. Do this in two different ways:

Question

a. Use the first letter of the output of ls –l to determine a file’s type.
b. Use the file type condition tests of the [[ expression ]] syntax to determine
a file’s type.

Answer 1

a.
$ function ft () {
> declare -i ord=0 dir=0 blk=0 char=0 fifo=0 symlnk=0 other=0
>
> for fn in *
> do
> case $(ls -ld "$fn" | cut -b1) in
> d)
> ((dir=$dir+1))
> ;;
> b)
> ((blk=$blk+1))
> ;;
> c)
> ((char=$char+1))
> ;;
> p)
> ((fifo=$fifo+1))
> ;;
> l)
> ((symlnk=$symlnk+1))
> ;;
> a-z)
> ((other=other+1))
> ;;
> *)
> ((ord=ord+1))
> ;;
> esac
> done
>
> echo $ord ordinary
> echo $dir directory
> echo $blk block
> echo $char character
> echo $fifo FIFO
> echo $symlnk symbolic link
> echo $other other
> }
b.
$ function ft2 () {
> declare -i ord=0 dir=0 blk=0 char=0 fifo=0 symlnk=0 other=0
>
> for fn in *
> do
> if [[ -h $fn ]]
> then ((symlnk=$symlnk+1))
> elif [[ -f $fn ]]
> then ((ord=ord+1))
> elif [[ -d $fn ]]
> then ((dir=$dir+1))
> elif [[ -b $fn ]]
> then ((blk=$blk+1))
> elif [[ -c $fn ]]
> then ((char=$char+1))
> elif [[ -p $fn ]]
> then ((fifo=$fifo+1))
> else
> ((other=other+1))
> fi
> done
>
> echo $ord ordinary
> echo $dir directory
> echo $blk block
> echo $char character
> echo $fifo FIFO
> echo $symlnk symbolic link
> echo $other other
> }